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221_Physics ProblemsTechnical Physics

# 221_Physics ProblemsTechnical Physics - 223 Chapter 8 P8.13...

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Chapter 8 223 P8.13 Using conservation of energy for the system of the Earth and the two objects (a) 500 400 300 1 2 500 300 2 .... . . kg m kg m bg af a f gg v =+ + v == 19 6 4 43 .. m s (b) Now we apply conservation of energy for the system of the 3.00 kg object and the Earth during the time interval between the instant when the string goes slack and the instant at which the 3.00 kg object reaches its highest position in its free fall. 1 2 100 2 . max vm g y g y y yy = = ∆∆ m m m FIG. P8.13 P8.14 mm 12 > (a) mgh m m v 11 2 2 2 1 2 + v mmg h = + 2 (b) Since m 2 has kinetic energy 1 2 2 2 mv , it will rise an additional height h determined from mg h 22 2 1 2 ∆= or from (a), h v g mmh + 2 2 The total height m 2 reaches is hh mh += + 2 1 . P8.15 The force of tension and subsequent force of compression in the
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