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228_Physics ProblemsTechnical Physics

228_Physics ProblemsTechnical Physics - 230 Potential...

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230 Potential Energy P8.33 (a) K m v v mv f i i = = − = 1 2 1 2 160 2 2 2 e j J (b) U mg = °= 3 00 30 0 73 5 . sin . . m J a f (c) The mechanical energy converted due to friction is 86.5 J f = = 86 5 28 8 . . J 3.00 m N (d) f n mg k k = = °= µ µ cos . . 30 0 28 8 N µ k = ° = 28 8 9 80 30 0 0 679 . . cos . . N 5.00 kg m s 2 b g e j FIG. P8.33 P8.34 Consider the whole motion: K U E K U i i f f + + = + mech (a) 0 1 2 0 80 0 9 80 1 000 50 0 800 3 600 200 1 2 80 0 784 000 40 000 720 000 1 2 80 0 2 24 000 80 0 24 5 1 1 2 2 2 2 2 + = + = = = = mgy f x f x mv v v v i f f f f . . . . . . . kg m s m N m N m kg J J J kg J kg m s 2 b g e j a fa f b ga f b g b g b g (b) Yes this is too fast for safety. (c) Now in the same energy equation as in part (a), x 2 is unknown, and x x 1 2 1 000 = m : 784 000 50 0 1 000 3 600 1 2 80 0 5 00 784 000
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