240_Physics ProblemsTechnical Physics

240_Physics ProblemsTechnical Physics - 242 Potential...

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242 Potential Energy (b) Let x represent the variable distance the chain has slipped since the start. Then length 5 x af remains on the table, with now F y = 0: +− − = nx g 50 λ g =− 5 fn x g g x g kk == µλ 045 2 04 .. Consider energies of the chain-Earth system at the initial moment when the chain starts to slip, and a final moment when x = 5, when the last link goes over the brink. Measure heights above the final position of the leading end of the chain. At the moment the final link slips off, the center of the chain is at y f = 4 meters. Originally, 5 meters of chain is at height 8 m and the middle of the dangling segment is at height 8 3 2 65 −= . m . KU E K U ii f f ++ = + mech : 0 1 2 11 22 2 = + F H G I K J z m gy m gy f dx mv mgy i k i f f bg 5836 5 2 0 4 1 2 88 4 40 0 19 5 2 00 0 400 4 00 32 0 27 5 2 00 0 400 2 400 27 5 2 00 5 00 0 400 12 5 4 00 22 5 4 00 22 5 9 80 742
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