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246_Physics ProblemsTechnical Physics

246_Physics ProblemsTechnical Physics - 248*P8.73 Potential...

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248 Potential Energy *P8.73 (a) At the top of the loop the car and riders are in free fall: F ma y y = : mg mv R down down = 2 v Rg = Energy of the car-riders-Earth system is conserved between release and top of loop: K U K U i gi f gf + = + : 0 1 2 2 2 + = + mgh mv mg R a f gh Rg g R h R = + = 1 2 2 2 50 a f . (b) Let h now represent the height 2 5 . R of the release point. At the bottom of the loop we have mgh mv b = 1 2 2 or v gh b 2 2 = F ma y y = : n mg mv R b b = 2 up b g n mg m gh R b = + 2 b g At the top of the loop,
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