246_Physics ProblemsTechnical Physics

246_Physics ProblemsTechnical Physics - 248 *P8.73...

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248 Potential Energy *P8.73 (a) At the top of the loop the car and riders are in free fall: Fm a yy = : mg mv R down down = 2 vR g = Energy of the car-riders-Earth system is conserved between release and top of loop: KU K U ig ifg f += + : 0 1 2 2 2 + mgh mv mg R a f gh Rg g R hR =+ = 1 2 2 250 a f . (b) Let h now represent the height 25 . R of the release point. At the bottom of the loop we have mgh mv b = 1 2 2 or vg h b 2 2 = a = : nm g mv R b b −= 2 up bg g mg h R b 2 At the top of the loop,
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