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252_Physics ProblemsTechnical Physics

252_Physics ProblemsTechnical Physics - 254 Linear Momentum...

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254 Linear Momentum and Collisions P9.2 (a) At maximum height v = 0 , so p = 0 . (b) Its original kinetic energy is its constant total energy, K mv i i = = = 1 2 1 2 0 100 15 0 11 2 2 2 . . . a f b g kg m s J . At the top all of this energy is gravitational. Halfway up, one-half of it is gravitational and the other half is kinetic: K v v = = = × = 5 62 1 2 0 100 2 5 62 10 6 2 . . . . J kg J 0.100 kg m s b g Then p v j = = m 0 100 10 6 . . ± kg m s b gb g p j = 1 06 . ± kg m s . P9.3 I have mass 85.0 kg and can jump to raise my center of gravity 25.0 cm. I leave the ground with speed given by v v a x x f i f i 2 2 2 = d i : 0 2 9 80 0 250 2 = v i . . m s m 2 e j a f v i =
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