252_Physics ProblemsTechnical Physics

252_Physics - 254 Linear Momentum and Collisions(a At maximum height v = 0 so p = 0(b P9.2 Its original kinetic energy is its constant total energy

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254 Linear Momentum and Collisions P9.2 (a) At maximum height v = 0 , so p = 0. (b) Its original kinetic energy is its constant total energy, Km v ii == = 1 2 1 2 0100 150 112 2 2 .. . a f bg kg m s J. At the top all of this energy is gravitational. Halfway up, one-half of it is gravitational and the other half is kinetic: Kv v = × = 562 1 2 25 6 2 10 6 2 . . J k g J 0.100 kg ms Then pv j m 106 ± kg m s b g pj =⋅ . ± kg m s . P9.3 I have mass 85.0 kg and can jump to raise my center of gravity 25.0 cm. I leave the ground with speed given by vv a xx fi 22 2 −= di : 02 9 8 0 0 2 5 0 2 −=− v i ±ms ±m 2 ej a f v i = 220 . m s Total momentum of the system of the Earth and me is conserved as I push the earth down and
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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