254 Linear Momentum and CollisionsP9.2(a)At maximum height v=0 , so p=0.(b)Its original kinetic energy is its constant total energy,Kmvii===1212010015011222...afbgkgm sJ.At the top all of this energy is gravitational. Halfway up, one-half of it is gravitational andthe other half is kinetic:Kvv=×=56212256210 62..J kgJ0.100 kgmsThen pvjm106±kgm sb gpj=⋅.±kg m s.P9.3I have mass 85.0 kg and can jump to raise my center of gravity 25.0 cm. I leave the ground withspeed given byvvaxxfi222−=−di:0298002502−=−vi±ms±m2ejafvi=220. msTotal momentum of the system of the Earth and me is conserved as I push the earth down and
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .