254_Physics ProblemsTechnical Physics

254_Physics - 256 P9.9 Linear Momentum and Collisions p = Ft f e ja = ma v sin 60.0 v sin 60.0f = 2mv sin 60.0 = 2b3.00 kg gb10.0 m sga0.866f p y =

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256 Linear Momentum and Collisions P9.9 ∆∆ pF = =− = ° ° = ° ° = ° == −⋅ t pm v v m v m v v v m v F p t yf y i y x x ej a f af bg b g a f cos . cos . sin . sin . sin . .. . . . . 60 0 60 0 0 60 0 60 0 2 60 0 2 3 00 10 0 0 866 52 0 52 0 0200 260 kg m s kg m s kg m s s N ave FIG. P9.9 P9.10 Assume the initial direction of the ball in the – x direction. (a) Impulse, Ip pp i i i ==− = = fi 00600 400 00600 500 540 ± ± . ± Ns (b) Work = = KK 1 2 500 270 22 . . a f a f J P9.11 Take x -axis toward the pitcher (a) pIp ix x fx += : 150 450 400 300 . . cos . . . cos . kg m s kg m s b g −° + = ° I x I x =⋅ 905 . N s iy y fy : . . sin . . . sin . kg m s kg m s + = ° I y Ii j =+ 612 . ± . ± (b) IF F F + + 1 2 0 4 00 20 0 1 2 mm m ... ms ms ms Fi j j m m ×× = + 24 0 10 9 05 6 12 377 255 3 ± . ± ±± s N s N P9.12 If the diver starts from rest and drops vertically into the water, the velocity just before impact is found from KU KU mv mgh v gh fg fig i + +=+ = 1 2 00 2 impact 2 impact
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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