258_Physics ProblemsTechnical Physics

258_Physics ProblemsTechnical Physics - 260 P9.24 Linear...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
260 Linear Momentum and Collisions P9.24 Energy is conserved for the bob-Earth system between bottom and top of swing. At the top the stiff rod is in compression and the bob nearly at rest. KUK U ii f f += + : 1 2 00 2 2 Mv Mg b +=+ A vg b 2 4 = A so b = 2 A Momentum of the bob-bullet system is conserved in the collision: mv m v Mg =+ 2 2 A ej v M m g = 4 A FIG. P9.24 P9.25 At impact, momentum of the clay-block system is conserved, so: mv m m v 11 2 2 bg After impact, the change in kinetic energy of the clay-block-surface system is equal to the increase in internal energy: 1 2 1 2 0 112 0 650 0 112 9 80 7 50 12 2 2 2 2 mmv f d mmg d v f += = + = af µ .. . . . kg kg m s m 2 v 2 2 95 6 = . m s 22 v 2 977 = . m s 12 0 10 0 112 9 77 3 1 . ×= kg kg m s b g v v 1 91 2 = . ms FIG. P9.25 P9.26 We assume equal firing speeds v and equal forces F required for the two bullets to push wood fibers apart. These equal forces act backward on the two bullets.
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online