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260_Physics ProblemsTechnical Physics

# 260_Physics ProblemsTechnical Physics - 262 P9.29 Linear...

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262 Linear Momentum and Collisions P9.29 p p xf xi = mv mv m O Y m s cos . cos . . 37 0 53 0 5 00 °+ °= b g 0 799 0 602 5 00 . . . v v O Y m s + = (1) p p mv mv yf yi = °− °= O Y sin . sin . 37 0 53 0 0 0 602 0 799 . . v v O Y = (2) Solving (1) and (2) simultaneously, v O m s = 3 99 . and v Y m s = 3 01 . . FIG. P9.29 P9.30 p p xf xi = : mv mv mv i O Y cos cos . θ θ + °− = 90 0 a f v v v i O Y cos sin θ θ + = (1) p p yf yi = : mv mv O Y sin sin . θ θ °− = 90 0 0 a f v v O Y sin cos θ θ = (2) From equation (2), v v O Y = F H G I K J cos sin θ θ (3) Substituting into equation (1), v v v i Y Y cos sin sin 2 θ θ θ F H G I K J + = so v v i Y cos sin sin 2 2 θ θ θ + = e j , and
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