263_Physics ProblemsTechnical Physics

263_Physics ProblemsTechnical Physics - Chapter 9 (a) v1 y...

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Chapter 9 265 (a) The object of mass m has final speed vv v yy i 12 32 == and the object of mass 3 m moves at xy ii 2 2 2 2 22 4 9 2 9 += + v i 2 2 2 2 2 3 (b) θ = F H G I K J tan 1 2 2 v v y x = F H G I K J tan . 1 2 3 3 2 35 3 v v i i P9.37 m 0 27 17 0 10 . k g v i = 0 (the parent nucleus) m 1 27 500 10 k g vj 1 6 600 10 . ± ms m 2 27 840 10 k g vi 2 6 400 10 . ± (a) mmm 11 33 0 vvv ++= where mmmm 3012 27 360 10 =−−= × k g FIG. P9.37 5 00 10 6 00 10 8 40 10 4 00 10 3 60 10 0 9 33 10 8 33 10 27 6 27 6 27 3 3 66 .. ± ± . . ± . ± ×× + + × = =− × × −−− ej e j e j ji v j (b) E m vm v =++ 1 2 1 2 1 2 2 2 2 E E × + × × + × × L N M O Q P 1 2 5 00 10 6 00 10 8 40 10 4 00 10 3 60 10 12 5 10 439 10 27 6 2 27 6 2 27 6 2 13 . . . e j e j e j J Section 9.5 The Center of Mass P9.38 The x -coordinate of the center of mass is x mx m
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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