268_Physics ProblemsTechnical Physics

268_Physics ProblemsTechnical Physics - F M I = − v lnF M...

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Unformatted text preview: F M I = − v lnF M I GH M JK GH M JK F M − kt IJ = − v lnFG 1 − k tIJ = M − kt , so v = − v lnG HMK H MK From Equation 9.41, v − 0 = v e ln i Now, M f f i i e f e i e i i M With the definition, Tp ≡ i , this becomes k F GH I JK F t IJ = 144 s , v = −b1 500 m sg lnG 1 − H 144 s K af v t = − v e ln 1 − With v e = 1 500 m s, and Tp a f vbm sg v (m/s) ts 0 224 488 808 132 3730 FH dt p IK OP F 1 Q = −v G GH 1 − e t Tp IF 1 I F v IF 1 JJ GH − T JK = GH T JK GG 1 − K H e p p t Tp I JJ , or K ve Tp − t 1 500 m s 144 s − t a f aem s j 2 10.4 20 12.1 40 14.4 60 17.9 80 23.4 100 34.1 120 62.5 132 125 continued on next page 140 120 100 80 60 40 20 0 t (s) FIG. P9.52(d) 140 0 2 a (m/s ) 120 ts 100 With v e = 1 500 m s, and Tp = 144 s , a = 80 (d) LM N d − v e ln 1 − Tt 60 af at = FIG. P9.52(b) 40 af dv at = = dt t (s) 140 2690 120 120 (c) 1220 1780 40 80 100 100 60 2500 2000 1500 1000 500 0 80 40 60 0 20 4000 3500 3000 20 (b) t Tp 20 (a) 0 P9.52 Linear Momentum and Collisions 0 270 ...
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