276 Linear Momentum and CollisionsP9.60(a)The initial momentum of the system is zero, whichremains constant throughout the motion.Therefore, when m1leaves the wedge, we musthavemv210wedgeblock+=or3 000 5004 000...kgkgm swedgebgbgbgv++=sovwedgems=−0667.(b)Using conservation of energy for the block-wedge-Earth system as the block slides down the smooth(frictionless) wedge, we havev= 4.00 m/sblockvwedge+xFIG. P9.60KUKKiiffblocksystemwedgeblocksystemwedge=++or001240001211222=+LNMOQP+−mghm
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .