275_Physics ProblemsTechnical Physics

275_Physics ProblemsTechnical Physics - Chapter 9 P9.62...

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Chapter 9 277 P9.62 Consider the motion of the firefighter during the three intervals: (1) before, (2) during, and (3) after collision with the platform. (a) While falling a height of 4.00 m, his speed changes from v i = 0 to v 1 as found from EKU KU ff i i =+− di bg , or KE U K U i i =−+ + When the initial position of the platform is taken as the zero level of gravitational potential, we have 1 2 180 0 0 1 2 mv fh mgh = °−++ cos a f Solving for v 1 gives v 1 v 2 FIG. P9.62 v fh mgh m 1 2 2 300400 750980400 75 0 681 = −+ = = af ch .. . . . . m s (b) During the inelastic collision, momentum is conserved; and if v 2 is the speed of the firefighter and platform just after collision, we have mv m M v
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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