278 Linear Momentum and Collisions*P9.63(a)Each object swings down according tomgRmv=1212MgRMv=1212vgR12=The collision:−+=++mvMvmM v112afvMmv21=−+Swinging up:1213522vgR+=+−°afafafcosR235=−°cos3520 4250 425142505750403gRMm Mm gRMmmMmM+=−−==cos...afafaf(b)No change is required if the force is different. The nature of the forces within the system ofcolliding objects does not affect the total momentum of the system. With strong magneticattraction, the heavier object will be moving somewhat faster and the lighter object fasterstill. Their extra kinetic energy will all be immediately converted into extra internal energywhen the objects latch together. Momentum conservation guarantees that none of the extraP9.64(a)Use conservation of the horizontal component ofmomentum for the system of the shell, the cannon,and the carriage, from just before to just after thecannon firing.ppxfxi=:mvmvshell shellcannon recoilcos.45 00°+=200 12545 05 0000bgcos.°+=vrecoilorvrecoilms354.FIG. P9.64(b)Use conservation of energy for the system of the cannon, the carriage, and the spring from
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