277_Physics ProblemsTechnical Physics

# 277_Physics ProblemsTechnical Physics - Chapter 9 P9.65(a...

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Chapter 9 279 P9.65 (a) Utilizing conservation of momentum, mv m m v v mm m gh v AB A A 11 1 2 1 12 1 1 2 629 =+ = + bg . m s (b) Utilizing the two equations, 1 2 2 gt y = and xvt A = 1 we combine them to find v x A y g 1 2 = x y v 1 i FIG. P9.65 From the data, v A 1 616 = . m s Most of the 2% difference between the values for speed is accounted for by the uncertainty in the data, estimated as 001 868 01 68 8 1 263 1 257 85 3 11% . . . . . . . +++ += . *P9.66 The ice cubes leave the track with speed determined by mgy mv i = 1 2 2 ; v == 298 15 542 .. . ±ms ±m 2 ej . Its speed at the apex of its trajectory is 40 415 .c o s . ms °= . For its collision with the wall we have mv F t mv Ft if F H G I K J
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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