Chapter 9279P9.65(a)Utilizing conservation ofmomentum,mvm m vvmmmghvABAA1112112112629=+=+≅bg. ms(b)Utilizing the two equations,122gty=and xvtA=1we combine them to findvxAyg12=xyv1iFIG. P9.65From the data, vA1616=. msMost of the 2% difference between the values for speed is accounted for by the uncertaintyin the data, estimated as 0018680168 81263125785 311%.......++++=.*P9.66The ice cubes leave the track with speed determined by mgymvi=122;v==29815542...±ms±m2ej.Its speed at the apex of its trajectory is 40415.cos.ms°=. For its collision with the wall wehavemvF tmvFtif−FHGIKJ
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .