280 Linear Momentum and CollisionsP9.67(a)Find the speed when the bullet emerges from theblock by using momentum conservation:mvMVmvii=+The block moves a distance of 5.00 cm. Assume foran approximation that the block quickly reaches itsmaximum velocity, Vi, and the bullet kept goingwith a constant velocity, v. The block thencompresses the spring and stops.400 m/s5.00 cmvFIG. P9.6712129005 00 10100150500 10400100222233MVkxVvmvMVmvii==×==−=×−×=−−−Nmmkgmskgm skgm skgbgejbgb g.......(b)∆∆∆EKU=+=×−×+×−−−1212129005 00 10323222.kgm skgm s±Nm±m∆E=−374 J, or there is an energy loss of 374 J .*P9.68The orbital speed of the Earth isvrTE7m3.156 10 s==××=×1496
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