282 Linear Momentum and CollisionsP9.71The force exerted by the table is equal to the change in momentumof each of the links in the chain.By the calculus chain rule of derivatives,Fdpdtdmvdtvdmdtmdvdt1===+af.We choose to account for the change in momentum of each link byhaving it pass from our area of interest just before it hits the table,so thatFIG. P9.71vdmdt≠0 and mdvdt=0.Since the mass per unit length is uniform, we can express each link of length dxas having a mass dm:dmMLdx=.The magnitude of the force on the falling chain is the force that will be necessary to stop each of the
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .