281_Physics ProblemsTechnical Physics

# 281_Physics ProblemsTechnical Physics - Chapter 9 P9.72 A...

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Chapter 9 283 P9.72 A picture one second later differs by showing five extra kilograms of sand moving on the belt. (a) p t x == 500 0750 100 375 .. . . kg m s s N bg b g (b) The only horizontal force on the sand is belt friction, so from pf t p xi xf += this is f p t x . N (c) The belt is in equilibrium: Fm a xx = : +− = Ff ext 0 and F ext N = . (d) WF r ° = cos . cos . θ 0 281 N 0.750 m J af (e) 1 2 1 2 5 00 0 750 1 41 2 2 mv . kg m s J (f) Friction between sand and belt converts half of the input work into extra internal energy. *P9.73 x mx m mR m mm ii i CM ++ + = + + 1 2 2 12 1 2 0 AA ch a f y x R A 2 FIG. P9.73 ANSWERS TO EVEN PROBLEMS P9.2 (a) 0; (b) 106 k gm s ; upward P9.20 0556 m P9.22 1.78 kN on the truck driver; 8.89 kN in the opposite direction on the car driver P9.4 (a) 600 . m s to the left; (b) 8.40 J
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