293_Physics ProblemsTechnical Physics

# 293_Physics ProblemsTechnical Physics - Chapter 10 P10.24...

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Chapter 10 295 P10.24 Treat the tire as consisting of three parts. The two sidewalls are each treated as a hollow cylinder of inner radius 16.5 cm, outer radius 30.5 cm, and height 0.635 cm. The tread region is treated as a hollow cylinder of inner radius 30.5 cm, outer radius 33.0 cm, and height 20.0 cm. Use Im R R =+ 1 2 1 2 2 2 ej for the moment of inertia of a hollow cylinder. Sidewall: m I =− × ×= = × π 0305 0165 635 10 110 10 144 1 2 1 44 0 165 0 305 8 68 10 22 33 2 .. . . . . . m m m k g m k g kg m m kg m 3 side 2 af e j bg Tread: m I = 0 330 0 305 0 200 1 10 10 11 0 1 2 11 0 0 330 0 305 1 11 3 . . . . . m m k g m k g kg m m kg m 3 tread 2 Entire Tire: II I total side tread 2 kg m kg m kg m =+= × + = 2 2868 10 111 128 2 . P10.25 Every particle in the door could be slid straight down into a high-density rod across its bottom, without changing the particle’s distance from the rotation axis of the door. Thus, a rod 0.870 m long
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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