Chapter 10303P10.48The moment of inertia of the cylinder isImr===⋅121281 61 5091 822...kgmkg m2bgafand the angular acceleration of the merry-go-round is found asατ=⋅=IFrIaf afafej50 01 5091 80817..N mkg mrad s22.At t=300.s, we find the angular velocityωω αω=+=it00 8173 002 45.rad ssrad s2and KI⋅=121291 82 4527622kg mrad sJ2.P10.49(a)Find the velocity of the CMKUmgRImgRImgRmRvRgRRgif+=+afaf0122243232322CM(b)vvRgL243CM(c)vmgRmRgCM22PivotR gFIG. P10.49*P10.50(a)The moment of inertia of the cord on the spool is12120 10 0150 094 16 1012224MRR+=×⋅−af..kgmmkg m2.The protruding strand has mass 100 161 6 1023−−kg mmkg..andIIMdMLMd=+=×++FHGIKJ⋅−−
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .