301_Physics ProblemsTechnical Physics

# 301_Physics ProblemsTechnical Physics - Chapter 10 P10.48...

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Chapter 10 303 P10.48 The moment of inertia of the cylinder is Im r == = 1 2 1 2 81 6 1 50 91 8 2 2 .. . kg m kg m 2 bg af and the angular acceleration of the merry-go-round is found as α τ = = I Fr I af a f a f ej 50 0 1 50 91 8 0817 . . N m kg m rad s 2 2 . At t = 300 . s, we find the angular velocity ωω α ω =+ = i t 0 0 817 3 00 2 45 . rad s s rad s 2 and KI = 1 2 1 2 91 8 2 45 276 2 2 kg m rad s J 2 . P10.49 (a) Find the velocity of the CM KU mgR I mgR I mgR mR vR g R Rg if += + a f a f 0 1 2 22 4 3 2 3 2 3 2 2 CM (b) vv Rg L 24 3 CM (c) v mgR m Rg CM 2 2 Pivot R g FIG. P10.49 *P10.50 (a) The moment of inertia of the cord on the spool is 1 2 1 2 0 1 0 015 0 09 4 16 10 1 2 2 2 4 MR R + a f . . kg m m kg m 2 . The protruding strand has mass 10 0 16 1 6 10 23 −− kg m m kg . . and I I Md ML Md = + = × + + F H G I K J
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