303_Physics ProblemsTechnical Physics

303_Physics ProblemsTechnical Physics - Chapter 10 P10.55...

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Chapter 10 305 P10.55 v x t v f == = = + 300 200 1 2 0 . . m 1.50 s ms di v f = 400 . m s and ω f f v r × = × 638 10 2 800 2 2 . . . . m rad s ej We ignore internal friction and suppose the can rolls without slipping. KK U E U mgy mv I I t g i g f if f trans rot mech trans rot 2 kg m s m kg m s rad s J J s ++ + = += + + F H G I K J °= + × F H G I K J =+ bg af b g 00 0 1 2 1 2 0 0 215 9 80 3 00 25 0 1 2 0215 1 2 267 172 7860 22 2 2 2 2 .. . s i n . . . I = 0951 121 10 2 4 . . kg m s s kg m 2 The height of the can is unnecessary data. P10.56 (a) Energy conservation for the system of the ball and the Earth between the horizontal section and top of loop: 1 2 1 2 1 2 1 2 1 2 1 2 2 3 1 2 1 2 2 3 5 6 5 6 2 2 2 2 21 2 1 2 2 2 2 2 1 1 2 2 2 2 mv I mgy mv I mv mr v r mgy mv mr v r vg y v = + + F H G I K J F H G I K J + F H G I K J F H G I K J ωω FIG. P10.56 vvg y 2 2 2 6 5 403 6 5 9 80 0 900 2 38 =− = = . . m 2 The centripetal acceleration is v r g 2 2 2 238 0450 12 6 > . . . m 2 Thus, the ball must be in contact with the track, with the track pushing downward on it. (b) 1 2 1 2 2 3 1 2 1 2 2 3 3 3 2 31 1 2 mv mr v r mgy mv mr v r + F H G
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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