Chapter 10305P10.55vxtvf====+∆∆300200120..m1.50 smsdivf=400.m s and ωffvr×=×−−638 10280022....mrad sejWe ignore internal friction and suppose the can rolls without slipping.KKUEUmgymvIItgigfifftransrotmechtransrot2kgm smkgm srad sJ Js+++=+=++FHGIKJ°=+×FHGIKJ=+−−bgafb g∆000121200 2159 803 0025 0120215122671727860222222...sin...I=⋅=×⋅−−0951121 1024..kg msskg m2The height of the can is unnecessary data.P10.56(a)Energy conservation for the system of the ball and theEarth between the horizontal section and top of loop:1212121212122312122356562222212122222112222mvImgymvImvmrvrmgymvmrvrvgyv=++FHGIKJFHGIKJ+FHGIKJFHGIKJωωFIG. P10.56vvgy22265403659 800 9002 38=−=−=..m2The centripetal acceleration is vrg222238045012 6>...m2Thus, the ball must be in contact with the track, with the track pushing downward on it.(b)1212231212233323112mvmrvrmgymvmrvr+FHG
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .