307_Physics ProblemsTechnical Physics

# 307_Physics ProblemsTechnical Physics - Chapter 10 P10.64...

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Chapter 10 309 P10.64 At the instant it comes off the wheel, the first drop has a velocity v 1 , directed upward. The magnitude of this velocity is found from KU K U mv mgh v gh ig ifg f += + +=+ = 1 2 00 2 1 2 11 1 or and the angular velocity of the wheel at the instant the first drop leaves is ω 1 1 1 2 2 == v R gh R . Similarly for the second drop: vg h 22 2 = and 2 2 2 2 2 v R gh R . The angular acceleration of the wheel is then a gh h R gh R gh R = = = ωω θπ π 2 2 1 2 21 2 2 2 2 2 1 2 a f bg . P10.65 KM vI ff f =+ 1 2 1 2 : UM g h 0; iii = 1 2 1 2 0 g h i i = : fNM g µµ θ cos ; = v r ; hd = sin and Im r = 1 2 2 (a) EE E fi =− or =+− fd K U K U ffi i −= + + F H G I K J
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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