309_Physics ProblemsTechnical Physics

309_Physics ProblemsTechnical Physics - Chapter 10 P10.68 =...

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Chapter 10 311 P10.68 θω = t t v == = ° ° θ ω 31.0 360 000574 0800 139 ch rev s m 0.005 74 s ms 900 rev 60 s . . = 31 ° v d FIG. P10.68 P10.69 τ f will oppose the torque due to the hanging object: τα ==− IT R f : f TR I =− (1) Now find T , I and α in given or known terms and substitute into equation (1). F T mg ma y =− = : Tm ga bg (2) also yv t at i =+ 2 2 a y t = 2 2 (3) and a R y Rt 2 2 : (4) IM R R MR F H G I K J L N M M O Q P P = 1 22 5 8 2 2 2 (5) FIG. P10.69 Substituting (2), (3), (4), and (5) into (1), we find f mg y t R MR y Rt Rmg y t My t F H G I K J −= F H G I K J L N M O Q P 2 5 8 2 2 5 4 2 2 2 P10.70 (a) WKU ∆∆ WK KU U fifi +− 0 1 2 1 2 1 2 1 2 1
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