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309_Physics ProblemsTechnical Physics

309_Physics ProblemsTechnical Physics - Chapter 10 P10.68 =...

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Chapter 10 311 P10.68 θ ω = t t v = = = = = ° ° θ ω 31.0 360 0 005 74 0 800 139 c h rev s m 0.005 74 s m s 900 rev 60 s . . = 31 ° v d ω θ FIG. P10.68 P10.69 τ f will oppose the torque due to the hanging object: τ α τ = = I TR f : τ α f TR I = (1) Now find T , I and α in given or known terms and substitute into equation (1). F T mg ma y = = − : T m g a = b g (2) also y v t at i = + 2 2 a y t = 2 2 (3) and α = = a R y Rt 2 2 : (4) I M R R MR = + F H G I K J L N M M O Q P P = 1 2 2 5 8 2 2 2 (5) FIG. P10.69 Substituting (2), (3), (4), and (5) into (1), we find τ f m g y t R MR y Rt R m g y t My t = F H G I K J = F H G I K J L N M O Q P 2 5 8 2 2 5 4 2 2 2 2 2 b g P10.70 (a) W K U = + W K K U U f i f i =
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