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336_Physics ProblemsTechnical Physics

336_Physics ProblemsTechnical Physics - 338*P11.38 Angular...

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338 Angular Momentum *P11.38 (a) Let ω be the angular speed of the signboard when it is vertical. 1 2 1 2 1 3 1 2 1 3 1 3 9 80 1 25 0 0 50 2 35 2 2 2 I Mgh ML Mg L g L ω ω θ ω θ = F H G I K J = = = ° = cos cos . cos . . . a f a f e j a f m s m rad s 2 θ Mg m v 1 2 L FIG. P11.38 (b) I I mvL f f i i ω ω = represents angular momentum conservation + F H G I K J = = + = + = 1 3 1 3 2 40 0 5 2 347 0 4 1 6 2 40 0 4 0 5 0 498 2 2 2 1 3 1 3 1 3 1 3 ML mL ML mvL ML mv M m L f i f i ω ω ω ω c h b ga fb g b gb g b g a f . . . . . . . . . kg m rad s kg m s kg kg m rad s (c) Let h CM = distance of center of mass from the axis of rotation. h CM kg m kg m kg kg m = + + = 2 40 0 25 0 4 0 50 2 40 0 4 0 285 7 . . . . . . . b ga f b ga f . Apply conservation of mechanical energy:
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