{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

340_Physics ProblemsTechnical Physics

340_Physics ProblemsTechnical Physics - 342 P11.45 Angular...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
342 Angular Momentum P11.45 (a) I m r m d m d m d m d i i = = F H G I K J + F H G I K J + F H G I K J = 2 2 2 2 2 4 3 3 2 3 7 3 m m m 1 2 3 d d P 2 3 d FIG. P11.45 (b) Think of the whole weight, 3 mg , acting at the center of gravity. τ = × = F H G I K J × = r F i j k d mg mgd 3 3 ± ± ± e j e j b g (c) α τ = = = I mgd md g d 3 7 3 7 2 counterclockwise (d) a r g d d g = = F H G I K J F H G I K J = α 3 7 2 3 2 7 up The angular acceleration is not constant, but energy is. K U E K U m g d I i f f + + = + + F H G I K
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern