Chapter 12353P12.6Let σrepresent the mass-per-face area. Avertical strip at position x, with width dxandheight x−30092.afhas massdmxdx=−92..The total mass isMdmxMxxdxMxxxx==−=FHGIKJ−+=FHGIKJLNMOQP=zzz=39969936292020320afej...xdx03.00 mxy1.00 my= (x —3.00)2/9FIG. P12.6The x-coordinate of the center of gravity isxxdmMdxxxxdxxxxCGm9.00m−=−+=−+LNMOQPz193919463926750 7502004320.....P12.7Let the fourth mass (8.00 kg) be placed at (x, y), thenxmxmxCGm++= −0300 40012 012 080015044....afSimilarly,yyCG++012 0 8 00.bgy. mP12.8In a uniform gravitational field, the center of mass and center of gravity of an object coincide. Thus,the center of gravity of the triangle is located at x=667m, y=233m(see the Example on thecenter of mass of a triangle in Chapter 9).
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .