363_Physics ProblemsTechnical Physics

363_Physics ProblemsTechnical Physics - 365 Chapter 12...

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Chapter 12 365 P12.40 When the concrete has cured and the pre-stressing tension has been released, the rod presses in on the concrete and with equal force, T 2 , the concrete produces tension in the rod. (a) In the concrete: stress = = F H G I K J 800 10 6 . N m s t r a i n 2 YY L L i a f Thus, L L Y i == × × stress Nm m 2 2 a f ej af 150 30 0 10 6 9 .. . or L = 400 10 0400 4 m m m . (b) In the concrete: stress × T A c 2 6 N m 2 , so T 2 64 8 00 10 50 0 10 40 0 × = . m kN 22 e j (c) For the rod: T A L L Y Ri 2 = F H G I K J steel so L TL AY i R = 2 steel L = × ×× = 150 10 200 10 200 4 41 0 3 N m N m m m e j (d) The rod in the finished concrete is 2.00 mm longer than its unstretched length. To remove stress from the concrete, one must stretch the rod 0.400 mm farther, by a total of 240 m m . (e) For the stretched rod around which the concrete is poured: T A L L YT L L T i R 1 1 1 3 0 240 10 1 50 10 20 0 10 48 0 = F H G I K J = F H G I K J = × F H G I K J = ∆∆ total steel total steel or m 1.50 m N m k N . . e j *P12.41 With
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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