384_Physics ProblemsTechnical Physics

384_Physics ProblemsTechnical Physics - 386 P13.8 Universal...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
386 Universal Gravitation P13.8 Let θ represent the angle each cable makes with the vertical, L the cable length, x the distance each ball scrunches in, and d = 1 m the original distance between them. Then rd x =− 2 is the separation of the balls. We have F y = 0: Tm g cos −= 0 F x = T Gmm r sin 2 0 FIG. P13.8 Then tan = Gmm rm g 2 x Lx Gm gd x 22 2 2 = a f xd x Gm g 2 2 a f . The factor Gm g is numerically small. There are two possibilities: either x is small or else dx 2 i s small. Possibility one : We can ignore x in comparison to d and L , obtaining x 1 667 10 100 98 45 2 11 m Nm kg kg ±ms m 2 a f ej bg = ×⋅ . . x 306 10 8 . m . The separation distance is r × = 12 3 0 6 1 0 1 0 0 06 1 3 8 m m m n m .. . . Possibility two : If 2 is small, x 05 . m and the equation becomes 45 0 5 2 11 . . . . m ±Nkg m a f a f a f r =
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

Ask a homework question - tutors are online