389_Physics ProblemsTechnical Physics

389_Physics ProblemsTechnical Physics - Chapter 13 P13.25...

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Chapter 13 391 P13.25 gg MG ra 12 22 == + yy =− g yyy =+ ggg xx 122 cos θ cos = + r ar ej gi 2 2 g x ± or g = + 2 32 MGr toward the center of mass FIG. P13.25 Section 13.6 Gravitational Potential Energy P13.26 (a) U GM m r E ×⋅ × × 6 67 10 5 98 10 100 6 37 2 00 10 477 10 11 24 6 9 .. . N m kg kg kg m J e j bg af . (b), (c) Planet and satellite exert forces of equal magnitude on each other, directed downward on the satellite and upward on the planet. F GM m r E × × = 2 11 24 2 6 67 10 5 98 10 100 569 N m kg kg kg 8.37 10 m N 6 e j P13.27 UG Mm r and g GM R E E = 2 so that M m RR mgR EE E F H G I K J = 1 3 3 U = × 2 3 1 000 9 80 6 37 10 4 17 10 61 0 kg m s m J 2 e j P13.28 The height attained is not small compared to the radius of the Earth, so Um g y = does not apply; U GM M r does. From launch to apogee at height h , KU E K U ii f f ++ = + mch : 1 2 00 2 Mv GM M
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