Chapter 13395P13.38The gravitational force supplies the needed centripetal acceleration.Thus,GM mRhmvEEE+=+bg22orvGMEE2=+(a)TrvEGMEE==++22πTGMEE=+23(b)vGMEE=+(c)Minimum energy input is∆EKUKUfgfigimin=+−−ejej.It is simplest tolaunch the satellite from a location on the equator, and launch it toward the east.This choice has the object starting with energyKmvii=122withvRRiEE2100286 400ππ. daysandUGM mRgiEE=−.Thus,∆EmGMGM mmRGMmREEEEEmin=+FHGIKJ−+−LNMMOQPP+1212486 400222sor∆EGMmRR hRmEEEmin=++LNMMOQPP−22286 4002sP13.39EGMmrtot2∆∆EGMmrrEifFHGIKJ=××+−+FHGIKJ=×=−2116 67 105 98 1021016370 10016370 200469 10469112438...ejkg10 mJ MJ3P13.40gGmrEEE=2gGmrUUU=2(a)
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .