395_Physics ProblemsTechnical Physics

# 395_Physics ProblemsTechnical Physics - Chapter 13 *P13.43...

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Chapter 13 397 *P13.43 (a) Energy conservation for the object-Earth system from firing to apex: KU mv GmM R GmM Rh g i g f i E E E E += + −= + ej 1 2 0 2 where 1 2 mv GmM R E E esc 2 = . Then 1 2 1 2 1 2 1 2 2 2 2 2 2 2 2 vv v R vR h R vR vR vR h Rv i E E i E E i E E E i E EE i E i Ei i + + = + = −+ = esc 2 esc 2 esc 2 esc 2 esc 2 esc 2 esc 2 esc 2 esc 2 esc 2 esc 2 esc 2 (b) h = × 637 10 11 2 8 76 100 10 6 2 22 7 . .. . m 8.76 m af (c) The fall of the meteorite is the time-reversal of the upward flight of the projectile, so it is described by the same energy equation R v h v i E i 2 3 2 7 67 8 4 11 1 2 1 0 251 10 6 37 10 2 51 10 =− + F H G I K J = + F H G I K J × ×+ × F H G I K J esc esc ms m m m . . . . (d) With i << esc , h v RvR GM Ei E E ≈= 2 2 2 2 esc . But g GM R E E = 2 , so h v g i = 2 2 , in agreement with 020 =+− − vg h i bg . P13.44 For a satellite in an orbit of radius
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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