Chapter 14415Section 14.2Variation of Pressure with DepthP14.6(a)PP gh=+ =×+051 013 101 0249 801 000ρ..Pakg mm sm32ejejbgP=×101 107. Pa(b)The gauge pressure is the difference in pressure between the water outside and the airinside the submarine, which we suppose is at 1.00 atmosphere.PPPghgaugePa=− ==×07100 10.The resultant inward force on the porthole is thenFP A==×=×gaugePamN1 00 100 1507 09 10725.πaf.P14.7FFel=fluidorkxghA=andhkxgA=h=××LNMOQP=−−1000500 10109 801 00 1016232Nmmkg mm smm2ejejej..FIG. P14.7P14.8Since the pressure is the same on both sides,FAFA1122=In this case,15 0002003 002=F.orF2225=NP14.9Fg80 09 80784kgm sN2When the cup barely supports the student, the normal force of theceiling is zero and the cup is in equilibrium.
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