420 Fluid MechanicsP14.25(a)Before the metal is immersed:FTMgy∑=− =10 orTMg1100980===...kgm sN2bgej(b)After the metal is immersed:FTBMgy∑=+− =2gBMgVgw2=−ρVM2700. kgkg m3Thus,ascalebBMgT1MgT2FIG. P14.25gB21000617=−FHGIKJ=..N kgmkg2700 kg mmsN332ej.*P14.26(a)FgTBFIG. P14.26(a)(b)Fy∑=0:−−+=15100NBB=25 0. N(c)The oil pushes horizontally inward on each side of the block.(d)String tension increases . The oil causes the water below to beunder greater pressure, and the water pushes up more stronglyon the bottom of the block.(e)Consider the equilibrium just before the string breaks:+==156025050N+NoiloilBBFor the buoyant force of the water we have
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .