418_Physics ProblemsTechnical Physics

418_Physics ProblemsTechnical Physics - 420 Fluid Mechanics...

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420 Fluid Mechanics P14.25 (a) Before the metal is immersed: FTM g y =− = 1 0 or TM g 1 100 980 == = .. . kg m s N 2 bg ej (b) After the metal is immersed: FTBM g y =+− = 2 gBM g V g w 2 =− ρ V M 2700 . k g kg m 3 Thus, a scale b B M g T 1 M g T 2 FIG. P14.25 gB 2 1000 617 = F H G I K J = . . N k g m kg 2700 kg m ms N 3 3 2 e j . *P14.26 (a) F g T B FIG. P14.26(a) (b) F y = 0: −− + = 15 10 0 N B B = 25 0 . N (c) The oil pushes horizontally inward on each side of the block. (d) String tension increases . The oil causes the water below to be under greater pressure, and the water pushes up more strongly on the bottom of the block. (e) Consider the equilibrium just before the string breaks: + = = 15 60 25 0 50 N + N oil oil B B For the buoyant force of the water we have
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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