420_Physics ProblemsTechnical Physics

420_Physics ProblemsTechnical Physics - 422*P14.30 Fluid...

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422 Fluid Mechanics *P14.30 (a) The weight of the ball must be equal to the buoyant force of the water: 126 4 3 31 2 6 670 13 . . . kg kg 4 1 000 kg m cm water outer 3 outer 3 gr g r = = × F H G I K J = ρπ π (b) The mass of the ball is determined by the density of aluminum: mV r r r r r i i i i == F H G I K J = F H G I K J ×= ×− = −− ρρ ππ Al Al 3 33 3 kg kg m m m m c m 4 3 4 3 2700 4 3 0067 1 11 10 3 01 10 189 10 574 0 3 3 44 3 4 .. a f ej *P14.31 Let A represent the horizontal cross-sectional area of the rod, which we presume to be constant. The rod is in equilibrium: F y = 0: −+ = = + mg B V g V g 0 0 whole rod fluid immersed 0 ALg A L h g =− af The density of the liquid is ρ = 0 L Lh . *P14.32 We use the result of Problem 14.31. For the rod floating in a liquid of density 098 . gc m 3 , = = −= 0 0 0 02 L L L LL . . . gcm cm cm 3 a f For floating in the dense liquid,
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