422 Fluid Mechanics*P14.30(a)The weight of the ball must be equal to the buoyant force of the water:12643312667013...kgkg4 1 000 kg mcmwaterouter3outer3grgr==×FHGIKJ=ρππ(b)The mass of the ball is determined by the density of aluminum:mVrrrrriiii==−FHGIKJ=FHGIKJ−×=×−=×=−−−ρρππAlAl3333kgkg mmm mcm434327004300671 11 103 01 10189 105740334434..afej*P14.31Let Arepresent the horizontal cross-sectional area of the rod, which we presume to be constant. Therod is in equilibrium:Fy∑=0:−+==−+mgBVgVg00whole rodfluid immersed0ALgA Lh g=−afThe density of the liquid isρ=−0LLh.*P14.32We use the result of Problem 14.31. For the rod floating in a liquid of density 098. gcm3,=−=−−=00002LLLLL...gcmcmcm3afFor floating in the dense liquid,
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .