422_Physics ProblemsTechnical Physics

422_Physics ProblemsTechnical Physics - 424 Fluid Mechanics...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
424 Fluid Mechanics Section 14.5 Fluid Dynamics Section 14.6 Bernoulli’s Equation P14.38 By Bernoulli’s equation, 800 10 1 2 1000 600 10 1 2 100016 200 10 1 2 100015 163 1 000 5 00 10 1 63 12 8 42 4 2 2 2 .. . . . ×+= ×+ ×= = == × = Nm ms kg s 22 2 bg ej vv v v dm dt Av ρπ FIG. P14.38 P14.39 Assuming the top is open to the atmosphere, then PP 10 = . Note 20 = . Flow rate −− 2 50 10 4 17 10 35 .m i n . m m s 33 . (a) AA 12 >> so << Assuming v 1 0 = , P v gy P v gy vg y 1 1 2 2 2 2 21 2 2980 160 177 ++ = = ρ a fa f . m s (b) Flow rate F H G I K J Av d 2 5 4 17 7 417 10 π a f 3 d = 173 10 173 3 m m *P14.40 Take point 1 at the free surface of the water in the tank and 2 inside the nozzle. (a) With the cork in place Pg y v y v 11 1 2 2 2 1 2 1 2 = ρρ becomes 02 98 75 0 0 0 = + + kg m m s m 32 ; 4 735 10 −= × . P a . For the stopper F x = 0 FF f PA PA f
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

Ask a homework question - tutors are online