427_Physics ProblemsTechnical Physics

# 427_Physics ProblemsTechnical Physics - Chapter 14...

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Chapter 14 429 Additional Problems P14.54 Consider the diagram and apply Bernoulli’s equation to points A and B, taking y = 0 at the level of point B, and recognizing that v A is approximately zero. This gives: Pg h L Pv g Aw w Bw B w ++ =+ + 1 2 0 1 2 0 2 2 ρρ θ af a f sin Now, recognize that PPP AB == atmosphere since both points are open to the atmosphere (neglecting variation of atmospheric pressure with altitude). Thus, we obtain h A Valve L B FIG. P14.54 vg h L v B B =− = ° = 2 2980 100 200 300 13 3 sin . . . sin . . ej ms m m 2 Now the problem reduces to one of projectile motion with vv yi B = sin . . 30 0 6 64 m s. Then, a y yf yi 22 2 =+∆ bg gives at the top of the arc (where yy = max and v yf = 0) 0 6 64 2 9 80 0 2 .. max 2 y or y max . = 2 25 m above the level where the water emerges . P14.55 When the balloon comes into equilibrium, we must have
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