Chapter 14429Additional ProblemsP14.54Consider the diagram and apply Bernoulli’sequation to points A and B, taking y=0 atthe level of point B, and recognizing that vAis approximately zero. This gives:PghLPvgAwwBwBw++−=++12012022ρρθafafsinNow, recognize that PPPAB==atmospheresince both points are open to the atmosphere(neglecting variation of atmosphericpressure with altitude). Thus, we obtainhAValveLBFIG. P14.54vghLvBB=−=−°=2298010020030013 3sin...sin..ejmsmm2Now the problem reduces to one of projectile motion with vvyiB=°=sin..30 06 64 m s. Then,ayyfyi222=+∆bggives at the top of the arc (where yy=maxand vyf=0)06 642 9 8002−−..max2yor ymax.=2 25 m above the level where the water emerges.P14.55When the balloon comes into equilibrium, we must have
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