Chapter 14431P14.61The torque isττ==zzdrdFFrom the figureτρρ=−=zygHywdygwHHbg0316The total force is given as122gwHIf this were applied at a height yeffsuch that the torque remainsunchanged, we have161232ρρgwHygwHeff=LNMOQPandyHeff=13.FIG. P14.61P14.62(a)The pressure on the surface of the two hemispheres is constantat all points, and the force on each element of surface area isdirected along the radius of the hemispheres. The applied forcealong the axis must balance the force on the “effective” area,which is the projection of the actual surface onto a planeperpendicular to the xaxis,AR=π2Therefore,FPPR02FIG. P14.62(b)For the values givenPP==×002040 1000 3000 2542 58 10..afm NP14.63Looking first at the top scale and the iron block, we have:TBFg1+=, ironwhere T1is the tension in the spring scale, Bis the buoyant force, and Fg, ironis the weight of the iron
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .