432 Fluid MechanicsP14.64Looking at the top scale and the iron block:TBFg1+=, FewhereBVgmg==FHGIKJρρρ00FeFeFeis the buoyant force exerted on the iron block by the oil.Thus,TFBmgmgg10=−FHGIKJ, FeFeFeFeorTmg101FHGIKJFeFeis the reading on the top scale.Now, consider the bottom scale, which exerts an upward force of T2on the beaker–oil–ironcombination.Fy∑=0:TTFFFggg120+−−−=,,,beakeroilFeFFT mmmgmggb21001=++−=++−−FHGIKJ,beakeroilFeFeFeFebgormmgb200+FHGIKJLNMMOQPPFeFeis the reading on the bottom scale.P14.65CugV=3083.ZnCuZnCugZnxVx Vxxxxafafaf+−=FHGIKJ=−FHGIKJFHGIKJ==51730831251717133896010900490 04%.........%.P14.66(a)From Fma∑=Bm gm gm a mm a−−==+shellHetotalshellHe(1)Whereg=waterandmVHeHe=Also,Vrd43633πPutting these into equation (1) above,
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .