436 Fluid MechanicsP14.72(a)The flow rate, Av, as given may be expressed as follows:25 00833833..liters30.0 sliters scm s3==.The area of the faucet tap is πcm2, so we can find the velocity asvAflow ratecm scmcm sm s328332652 65..(b)We choose point 1 to be in the entrance pipe and point 2 to be at the faucet tap. Av1122=gives v10295=.m s. Bernoulli’s equation is:PPv vgy y1222122112−=− +−ρρejbgand gives3312102 650 295109 802 00−+kg mm sm skg mm sm332bgejaf..orPgaugePa=−=×4231 10..P14.73(a)Since the upward buoyant force is balanced by the weight of the sphere,mgVgR g1343FHGIKJ.In this problem, ρ=078945. gcm3at 20.0°C, and R=100.cm so we find:mR13343433307=FHGIKJ=LNMOQP=ρπ.gcmcm
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .