435_Physics ProblemsTechnical Physics

# 435_Physics ProblemsTechnical Physics - Chapter 14*P14.74(a...

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Chapter 14 437 *P14.74 (a) Take point 1 at the free water surface in the tank and point 2 at the bottom end of the tube: P gy v P gy v P gd P v v gd 1 1 1 2 2 2 2 2 0 0 2 2 2 1 2 1 2 0 0 1 2 2 + + = + + + + = + + = ρ ρ ρ ρ ρ ρ The volume flow rate is V t Ah t v A = = 2 . Then t Ah v A Ah A gd = = 2 2 . (b) t = × = 0 5 0 5 2 9 8 10 44 6 2 4 . . . . m m 2 10 m m s m s 2 2 a f e j *P14.75 (a) For diverging stream lines that pass just above and just below the hydrofoil we have P gy v P gy v t t t b b b + + = + + ρ ρ ρ ρ 1 2 1 2 2 2 . Ignoring the buoyant force means taking y y t b P nv P v P P v n t b b b b t b + = + = 1 2 1 2 1 2 1 2 2 2 2 ρ ρ ρ b g e j The lift force is P P A v n A b t b = b g e j 1 2 1 2 2 ρ . (b) For liftoff,
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