445_Physics ProblemsTechnical Physics

445_Physics ProblemsTechnical Physics - Chapter 15 P15.21...

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Chapter 15 447 P15.21 (a) Ek A = 1 2 2 , so if ′= AA 2, ′ = == A k A E 1 2 1 2 24 2 2 af a f Therefore E increases by factor of 4 . (b) v k m A max = , so if A is doubled, v max is doubled . (c) a k m A max = , so if A is doubled, a max also doubles . (d) T m k = 2 π is independent of A , so the period is unchanged . *P15.22 (a) yy v t a t fiy i y =+ + 1 2 2 −= + + = = 11 0 0 1 2 98 22 150 2 m m s ms m s 2 2 . . . ej t t (b) Take the initial point where she steps off the bridge and the final point at the bottom of her motion. KU U mgy kx k k gs i f ++ = + +=++ = = 00 0 0 1 2 65 9 8 1 2 25 73 4 2 2 kg m s 36 m m ±Nm 2 . . (c) The spring extension at equilibrium is x F k = 65 868 kg 9.8 m s 73.4 N m m 2 . , so this point is 11 868 197 += .. m m below the bridge and the amplitude of her oscillation is
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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