447_Physics ProblemsTechnical Physics

447_Physics ProblemsTechnical Physics - Chapter 15 P15.26...

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Unformatted text preview: Chapter 15 P15.26 The angle of the crank pin is θ = ωt . Its x-coordinate is ω Piston x = A cos θ = A cos ωt A where A is the distance from the center of the wheel to the crank pin. This is of the form x = A cos ωt + φ , so the yoke and piston rod move with simple harmonic motion. b Section 15.5 P15.27 (a) g FIG. P15.26 The Pendulum T = 2π L= (b) x = –A gT 2 4π 2 L g e9.80 m s ja12.0 sf 2 = Tmoon = 2π 4π 2 L = 2π g moon 2 = 35.7 m 35.7 m 1.67 m s 2 = 29.1 s TT = 2π LT gT TC = 2π LC gC We know TT = TC = 2.00 s For which, we see LT LC = gT gC or P15.29 The period in Tokyo is and the period in Cambridge is P15.28 g C LC 0.994 2 = = = 1.001 5 g T LT 0.992 7 The swinging box is a physical pendulum with period T = 2π I . mgd The moment of inertia is given approximately by I= 1 mL2 (treating the box as a rod suspended from one end). 3 Then, with L ≈ 1.0 m and d ≈ T ≈ 2π 1 3 L , 2 mL2 mg ch L 2 = 2π a f 2 1.0 m 2L = 2π = 1.6 s or T ~ 10 0 s . 2 3g 3 9.8 m s e j x ( t) 449 ...
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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