Chapter 15451P15.33Referring to the sketch we haveFmg=−sinθandtan=xRFor small displacements,tansinθθ≈andFmgRxkxSince the restoring force is proportional to the displacement fromequilibrium, the motion is simple harmonic motion.Comparing toxω2shows ==kmgR.FIG. P15.33P15.34(a)T=total measured time50The measured periods are:Length, mPeriod, sLTafa f1 0000 7500 5001 996 1 7321 422...(b)TLg=2πsogLT=422The calculated values for gare:Period, sms2Tgafej1 996 1 732 1 42299198797643222.214.171.1241.0L, mT2, s2FIG. P15.34Thus, gave2=985.this agrees with the accepted value of g=980
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .