458 Oscillatory Motion(b)The energy of the m1-spring system at equilibrium is:12129 000 5001125122mv==...kgm sJbgbg.This is also equal to 122kA′af, where ′Ais the amplitude of the m1-spring system.Therefore,121002af′=A.or ′=A0150. m.The period of the m1-spring system is Tmk218851πsand it takes 140471T=.s after it passes the equilibrium point for the spring to become fullystretched the first time. The distance separating m1and m2at this time is:DvTA=FHGIKJ−′=−==40 5000 4710 1500 085 68 56...mssmcm.P15.53dxdtA222FHGIKJ=maxωfnmgmAAgsssmax.=µµµ22662±cmfnmgBPBsFIG. P15.53P15.54The maximum acceleration of the oscillating system is aAAfmaxωπ2224. The friction forceexerted between the two blocks must be capable of accelerating block B at this rate. Thus, if Block
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