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469_Physics ProblemsTechnical Physics

469_Physics ProblemsTechnical Physics - Chapter 15(f T= a...

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Chapter 15 471 (f) T = + = + = 2 0 4 0 25 0 3 9 8 0 024 12 0 3 3 06 0 497 3 56 . . . . . . . . . a fb g e j b gb g kg m s m s N m kg 12 N m s s s 2 π Then f T = = 1 0 281 . Hz . (g) T mg kv m k s k = + 2 µ µ π b g increases as m increases, so the frequency decreases . (h) As k increases, T decreases and f increases . (i) As v increases, T decreases and f increases . (j) As µ µ s k b g increases, T increases and f decreases . *P15.75 (a) Newton’s law of universal gravitation is F GMm r Gm r r = − = − F H G I K J 2 2 3 4 3 π ρ Thus, F Gm r = − F H G I K J 4 3 πρ Which is of Hooke’s law form with k Gm = 4 3 πρ (b) The sack of mail moves without friction according to F H G I K J = 4 3 πρ Gmr ma a Gr r = − F H G I K J = − 4 3 2 πρ ω Since acceleration is a negative constant times excursion from equilibrium, it executes SHM with ω πρ = 4 3 G and period T
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