477_Physics ProblemsTechnical Physics

# 477_Physics ProblemsTechnical Physics - Chapter 16 P16.17 f...

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Chapter 16 479 P16.17 yx t =+ F H G I K J 0120 8 4 .s i n m a f π (a) v dy dt = : xx t F H G I K J 0120 4 8 4 .c o s a fa f v 0200 151 .. s, 1.60 m m s af =− a dv dt = : ax t + F H G I K J 4 8 4 2 i n m a fa f a 0 . s, 1.60 m = (b) k == ππ λ 8 2 : = 16 0 . m ωπ 4 2 T : T = 0500 . s v T = 16 0 32 0 . . m 0.500 s ms P16.18 (a) Let us write the wave function as yx t A kx t ,s i n bg b g + ωφ yA 00 2 i n . φ m dy dt A 200 , cos . Also, ω = 22 00250 80 0 T . . s s Ax v i i 2 2 2 00200 80 0 F H G I K J F H G I K J . . . m s A = 0021 5 m (b) A A sin cos . .t a n . = 251 2 80 0 Your calculator’s answer tan . . −= 1 119 rad has a negative sine and positive cosine, just the reverse of what is required. You must look beyond your calculator to find φπ = 195 rad rad (c) vA y , . max m s = 00215 800
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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