Chapter 16483P16.32Refer to the diagrams. From the free-body diagram of point A:FTMgy∑=⇒=01sinθandFTTx∑=⇒=01cosθCombining these equations to eliminate T1gives the tension in thestring connecting points Aand Bas: TMg=tanθ.The speed of transverse waves in this segment of string is thenvTMgLmMgmL===µθθtantanand the time for a pulse to travel from Ato BistvmLMgL==24tanθ.MMDL/4L/4ABθL/2ddθTMgθAT1FIG. P16.32*P16.33(a)fhas units Hzs=1, so Tf=1has units of seconds, s. For the other Twe have Tv=µ2,with units kgmmskg msN222=⋅=.(b)The first Tis periodof time; the second is forceof tension.Section 16.4Reflection and TransmissionProblem 7 in Chapter 18 can be assigned with this section.Section 16.5
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