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483_Physics ProblemsTechnical Physics

# 483_Physics ProblemsTechnical Physics - Chapter 16*P16.40...

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Chapter 16 485 *P16.40 Comparing yt x =− + F H G I K J 035 10 3 4 .s i n ππ π with yA k x t A tk x + + sin sin ωφ ω φπ bg b g we have k m = 3 , ωπ = 10 s , A = . m . Then vf f k == = λπ λ 2 2 10 3 333 s m ms . . (a) The rate of energy transport is P × = 1 2 1 2 75 10 10 0 35 3 33 15 1 22 3 2 2 µω Av k g m m s W ej af .. . . (b) The energy per cycle is ET A = × = 1 2 1 2 75 10 10 0 35 2 302 3 2 2 kg m s m m 3 J a f . P16.41 Originally, 0 0 0 1 2 1 2 1 2 = = = µ ωµ A T AT The doubled string will have doubled mass-per-length. Presuming that we hold tension constant, it can carry power larger by 2 times. 2 1 2 2 0 = *P16.42 As for a strong wave, the rate of energy transfer is proportional to the square of the amplitude and to
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