486_Physics ProblemsTechnical Physics

486_Physics ProblemsTechnical Physics - 488 P16.48 Wave...

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488 Wave Motion P16.48 Compare the given wave function yx t =− 400 200 300 .s i n . . af cm to the general form yA k x t sin ω to find (a) amplitude A == 00400 .. cm m (b) k 2 1 π λ . c m and λπ cm m 00314 . (c) ωπ 23 0 0 1 f s and f = 0477 H z (d) T f 1 209 s (e) The minus sign indicates that the wave is traveling in the positive -direction x . P16.49 (a) Let ut x + 10 3 4 ππ du dt dx dt = 10 3 0 at a point of constant phase dx dt 10 3 333 m s The velocity is in the positive -direction x . (b) y 0 100 0 0 350 0 300 4 00548 548 ., . s i n. . . bg a f + F H G I K J = − m m c m (c) k 2 3 : = 0667 m 21 0 f : f = 500 H z (d) v y t tx y = + F H G I K J 0 350 10 10 3 4 .c o s a f v y , max ms 10 0 350 11 0 a f *P16.50 (a) 0 175 0 350 99 6 s i n . m r a d s = a f t ∴= sin . . 99 6 0 5 rad s t The smallest two angles for which the sine function is 0.5 are 30° and 150°, i.e., 0.523 6 rad and 2.618 rad. 99 6 0 523 6 1 rad s rad t = , thus t 1 526 = m s 99 6
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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