492_Physics ProblemsTechnical Physics

492_Physics ProblemsTechnical Physics - 494 Wave Motion af...

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494 Wave Motion P16.67 (a) P xA v A e kk Ae bx bx af == F H G I K J = −− 1 2 1 22 2 0 3 0 µω ωµ ω (b) 0 2 3 0 2 = k A (c) x e bx a f 0 2 = P16.68 v = 4450 468 130 km 9.50 h km h m s d v g = 2 2 130 980 1730 ms m 2 bg ej . *P16.69 (a) µ x is a linear function, so it is of the form xm xb =+ To have µµ 0 0 = we require b = 0 . Then Lm L L ==+ 0 so m L L = 0 Then x x L L = + 0 0 (b) From v dx dt = , the time required to move from x to xd x + is dx v . The time required to move from 0 to L is t dx v dx T xdx t T x LL dx L t T L x L t L T t L T L T L L L L L L L L L L = = + F H G I K J F H G I K J F H G I K J = F H G I K J + F H G I K J = = −+ + zz z z 00 0 0 0 12 0 0 0 0 0 0 32 3 2 0 0 0 0 0 1 1 11 2 3 2 3 e j + = ++ + F H G I K J 0 0 2
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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