509_Physics ProblemsTechnical Physics

# 509_Physics - Chapter 17 P17.39 f= Approaching ambulance 511 f b1 v vg S f f = Departing ambulance d1 b v vgi F vI F vI 560G 1 J = 480G 1 J H vK H

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Chapter 17 511 P17.39 Approaching ambulance: ′= f f vv S 1 bg Departing ambulance: ′′ = −− f f S 1 di Since f 560 Hz and ′′ = f 480 Hz 560 1 480 1 F H G I K J =+ F H G I K J v v v v SS 1040 800 80 0 343 26 4 v v v S S = == . . . af ms P17.40 (a) The maximum speed of the speaker is described by 1 2 1 2 20 0 500 0500 100 22 mv kA v k m A max max . . .. = = Nm kg m m s The frequencies heard by the stationary observer range from + F H G I K J ff v min max to F H G I K J v max max where v is the speed of sound. + F H G I K J = = F H G I K J = f f min max . . 440 343 1 00 439 440 343 1 00 441 Hz 343 m s Hz Hz 343 m s Hz (b) β π = F H G I K J = F H G I K J 10 10 4 0 2 0 dB dB log log I I r I The maximum intensity level (of 60.0 dB) occurs at rr min . 1 00 m. The minimum intensity level occurs when the speaker is farthest from the listener (i.e., when
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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