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509_Physics ProblemsTechnical Physics

509_Physics ProblemsTechnical Physics - Chapter 17 P17.39...

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Chapter 17 511 P17.39 Approaching ambulance: ′ = f f v v S 1 b g Departing ambulance: ′′ = − − f f v v S 1 b g d i Since ′ = f 560 Hz and ′′ = f 480 Hz 560 1 480 1 F H G I K J = + F H G I K J v v v v S S 1 040 80 0 80 0 343 1 040 26 4 v v v S S = = = . . . a f m s m s P17.40 (a) The maximum speed of the speaker is described by 1 2 1 2 20 0 5 00 0 500 1 00 2 2 mv kA v k m A max max . . . . = = = = N m kg m m s a f The frequencies heard by the stationary observer range from = + F H G I K J f f v v v min max to = F H G I K J f f v v v max max where v is the speed of sound. = + F H G I K J = = F H G I K J = f f min max . . 440 343 1 00 439 440 343 1 00 441 Hz 343 m s m s m s Hz Hz 343 m s m s m s Hz (b) β π = F H G I K J = F H G I K J 10 10 4 0 2 0 dB dB log log I I r I The maximum intensity level (of 60.0 dB) occurs at r r = = min . 1 00 m. The minimum intensity
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